Jawabanmu

2014-02-10T20:58:26+07:00
X kuadrat-3x-2= (x-2)(x+1)





tdk ad d plhnx..
pilihannya gmn?
a.x2-8x-1=0
b.x2+8x-1=0
c.x2-8x+3=0
d.x2+4x-1+0
e.x2+4x+3+0
2014-02-10T21:05:45+07:00
x²-3x-2
x₁+x₂ = -b/a = 3
x₁.x₂ = c/a = -2

x₁ = 2x₁+1
x₂ = 2x₂+1

x₁+x₂ = 2x₁+1+2x₂+1
         = 2 (x₁+x₂) + 2
         = 2.3 + 2
         = 8
x₁.x₂ = (2x₁+1)(2x₂+1)
        = 2(x₁.x₂)+2(x₁+x₂)+1
        = 2.-2+2.3+1
        = 3
x²-8x+3=0