Jawabanmu

2014-08-09T21:49:42+07:00
(3k-5) (k²+2k-6)
= (3k·k²)+(3k·2k)+(3k·-6)+(-5·k²)+(-5·2k)+(-5·-6)
= 3k³+6k²-18k-5k²-10k+30
=3k³+k²-28k+30