Jawabanmu

2014-08-07T19:57:14+07:00
Jumlah mol glikol :   \frac{31 gram}{50 mr C2H6O2} = 0,62 mol
massa pelarut : 91 mL = 91 gr = 0,091 kg
molalitas = l \frac{jumlah mol}{massa pelarut}
m =  \frac{n}{p}  \frac{0,62}{0,091} = 6,183 mol  kg^{-1}