Jawabanmu

2014-08-06T17:41:00+07:00
Misalkan u = 2x-1
du = 2 dx

dv/dx = akr(x)
v = 2/3 x . akar(x)

int (u dv) = uv - int (v du)
= (2x-1)(2/3(x.akr(x)) - int (2/3 x. akr (x))2dx
= (2x-1)(2/3(x.akr(x)) - 8/15 x^2 . akr (x)