Jawabanmu

2014-02-03T23:10:48+07:00
A.{H}+ = a.Ma karena H2SO4 bersifat asam kuat
[H+] = 2. (0.01 mol/0.1L)
[H+] = 2 (0.1M)
[H+] = 0.2 M atau 2. 10^-1
pH = -log [H+]
pH = - log (0.2)
pH = 1-log 2 atau 1 - 0.301
pH = 0,698

b [H+] = \sqrt{Ka . Ma}
[H+] = \sqrt{10 ^{-6}  (0.1/5x10 ^{-2}  )
[H+] = 10^-3.x  \sqrt{2}
[H+] = 1.41 x 10^-3 M
pH = -log [H+]
pH = -log [1,41 x 10^-3}
pH = 3-log 1,41

c. [H+] = alpha .Ma karena CH3COOH bersifat asam lemah
[H+] = 0.1. (0.1 mol/0.2L)
[H+] = 0.1 (0.5M)
[H+] = 0.05 M atau 5. 10^-2
pH = -log [H+]
pH = - log (0.05)
pH = 2-log 5 atau 2 - 0,69
pH = 1,30