Jawabanmu

2014-07-18T21:02:20+07:00
Y = x^e^x = e^((e^x) ln x)
u = e^x ln x
y’ = [d(e^u)/du] [d(e^x ln x)/dx]
= [e^u] [(e^x (x ln x + 1))/x]
= e^(e^x ln x) [(e^x(x ln x + 1))/x], atau
= (x ln x + 1).e^x.x^(e^x - 1)
di copy dari fb forum matematika di jawab oleh:
NurFat