Jawabanmu

2014-07-06T13:51:32+07:00
Jumlah mol NaOH = 0,2 x 500 = 100mmol
jumlah mol CH3COOH = 0,6 x 500 = 300mmol
              NaOH + CH3COOH -----> CH3COONa + H2O 
mula ; 100mmol     300mmol
bereaksi; 100mmol    100mmol       100mmol      100mmol
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akhir ;   0          200                         100                   100

[H+] = pka -log a/g
       = 5 x 10 ^-5 -log 200/100 = 5 x 10 ^ -5 - log 2 = 5 x 10^-5 - 0,30 = 4,7 x 10^-5
 PH= 5 -log 4,7 
4,53 x 10 ^-5 mungkin?? maaf kalo salah
klo kta aku mah isinya th 9