Jawabanmu

Jawaban paling cerdas!
2014-07-04T06:39:45+07:00
 f(1/√2 - 1) = (1/√2 - 1)⁴ - 2(1/√2 - 1)³ - 2(1/√2 - 1) + 7
<>  {(1/√2)⁴- 4*(1/√2)³*(1) + 6*(1/√2)²*(1)² - 4*(1/√2)*(1)³ + (1)⁴} - [2 {(1/√2)³ - 3(1/√2)²(1) + 3(1/√2)(1)² - (1)³}] - 2/√2 + 2 + 7
<> {(1/4) - 4(1/2√2) + 6(1/2) - 4 (1/√2) + 1} - [2 {(1/2√2) - 3 (1/2) + (3/√2) - 1}] - (2/√2) + 9
<> { (1/4) - (2/√2) + 3 - (4/√2) + 1 } - [2 {(1/2√2 ) - (3/2) +(3/√2) - 1}] - (2/√2) + 9
<> (1/4) - (2/√2) + 3 - (4/√2) + 1 - √2 + 3 - (6/√2) + 2 - (2/√2) + 9
<> -(2/√2) - (4/√2) - (6/√2) - (2/√2) - √2 + (1/4) + 3 + 1 + 3 + 2 + 9
<> -(14/√2) - √2 + (1/4) + 18
<> -(7√2) - √2 + (73/4)
<=> (73/4) - 8√2 atau 73 - 32√2
*maaf kalau salah hitung*

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