Jawabanmu

2014-06-30T13:05:21+07:00
(3 sinx+4 cosy)^2+(3 cosx+4 siny)^2=9+16+24 sin(x+y)=25+24 sin(x+y) So,Minimum value of (3 cosx+4 sin y)=(25-25+(24×0))^(1/2)=0
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