Jawabanmu

2014-06-24T17:49:56+07:00
Misal ^{2} log x = y
soalnya jadi :
y(5-y) = 6
5y-y^2 = 6
y^2-5y+6 = 0
(y-2)(y-3) = 0
y=2 y=3
y=2 ^{2} log x_{1}  = 2
 x_{1}  = 2^2 = 4
y=3^{2} log x_{2}  = 3
 x_{2}  = 2^3 = 8
 x_{1}^2 + x_{2}^2 = 16+64=80
Semoga Membantu ;D