Jawabanmu

Jawaban paling cerdas!
2014-06-19T11:23:40+07:00
Anggap aja kaya
A.C=X
A(invers)A.C=A(invers)x
C=A(invers).X
  \left[\begin{array}{ccc}x\\y\end{array}\right] =  \left[\begin{array}{ccc}sina\\cosa\end{array}\right] 1/sin²α+cos²α  \left[\begin{array}{ccc}sina&cosa\\-cosa&sina\end{array}\right]
x=sin²α+cos²α=1
y=-cosαsinα+cosαsinα=0
1 5 1