Jawabanmu

2014-06-18T22:50:11+07:00

  kosentrasi H+ = akar Ka . M

=  \sqrt{10 ^{-8} }.  10^{-2}
=  \sqrt{10 ^{-8} }
= 10^{-4} [/tex]

ph = - log  kosentrasi H+
= - log 10^-8
= 8

2014-06-18T22:52:08+07:00
HCN termasuk asam lemah.
[ H^{+} ]= \sqrt{Ka.Ma} = \sqrt{10^{-6}.10^{-2}}  = 10^{-4}

pH=-log [ H^{+} ]
= - log  10^{-4}
= 4