Jawabanmu

2014-02-02T22:09:38+07:00
PH = 3
[H⁺]= 10⁻³
[H⁺] =  \sqrt{[HA] . Ka}
10⁻³ =  \sqrt{0,2.Ka}
10⁻⁶ = 0,2. Ka
Ka =  5 x 10⁻⁶

α =  \sqrt{Ka/ [HA]}
α =  \sqrt 5 x 10⁻⁶ . 0,2
   =  \sqrt 25 x 10⁻⁶
   = 5 x 10⁻³
   = 0,005

maaf kalo salah hitung
2014-02-02T22:15:06+07:00
PH = 3
[ H^{+} ] =  10^{-3}
[ H^{+} ] =  \sqrt{Ka . M}
 10^{-3}] =  \sqrt{Ka . 0,2}
 10^{-9} = Ka . 0,2 \\ Ka =   \frac{ 10^{-9} }{0,2}  \\ Ka = 5 .  10^{-9}
α =  \sqrt{ \frac{Ka}{M} }
α =  \sqrt{ \frac{5 .  10^{-9} }{0,2} }
α =  \sqrt{2,5 .  10^{-8} }
α = 1,58 .  10^{-4}
terima kasih
yaa, maaf klo salah hitung :')
okeee