Jawabanmu

2014-06-16T21:17:51+07:00
y'' + 2y' + y =x +  e^{-X}

solusi umum
   r^{2} + 2r + 1 =0
        (r + 1)^{2} =0
                  akar-akar  persamaan
                        r_{1} = r_{2} = -1
y_{h} = C_{1} e^{r_{1}X} +  C_{2}X e^{r_{2}X}
y_{h} = C_{1} e^{-1X} +  C_{2}X e^{-1X}
y_{h} = C_{1} e^{-X} +  C_{2}X e^{-X}



termakasih,kalau solusi khusus gimana?