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2014-06-15T20:52:02+07:00
A.) mol = massa / Mr = 11,2 / 56 = 0,2 mol
     jumlah partikel = mol x L = 0,2 x 6,02 x 10²³ = 1,204 x 10²³

b.) Mr CaCO₃ = 1.40 + 1.12 + 3.16 = 100
     massa = mol x Mr = 0,25 x 100 = 25 gr
1 5 1
2014-06-15T20:52:35+07:00
A) n=m/ar
=11,2/56
=0,2mol
b) m=n*mr
=0,25*(1*40+1*12+3*16)
=0,25*100
=25 gr