Jawabanmu

2013-12-10T16:43:59+07:00
Diketahui :
Q1 = 5x  10^{-2}
Q2 = 6x 10^{-4}
R = 3 cm = 3. 10^{-2} m
k = 9x 10^{9}

Ditanya :
Fc ?

Jawab :

Hukum Coulomb

F = k \frac{Q1.Q2}{ R^{2} }
= 9x 10^{9}  \frac{(5x 10^{-2})(6x 10^{-4})  }{(3x 10^{-2})^{2}  }
=3x 10^{8} N