Jawabanmu

2014-06-13T19:42:34+07:00
PbCl2 ⇒ Pb2+ +2Cl-
10^-2       10^-2   2x10^-2   
Ksp = (10^-2)(4x10^-4) = 4 x 10^-6

CaCl2 ⇒ Ca2+ + 2Cl-
5x10^-2   5x10^-2  10^-1

PbCl2 ⇒ Pb2+ + 2Cl-
s             s          2s 

Ksp = (Pb2+)(Cl-)²
4x10^-6 = (s)(10^-1)²
s = 4 x 10^-4

PbCl2 = 4x10^-4

M= (gr/Mr)(1000/V)
4x10^-4 = (gr/278)(1000/100)
gr = 0,011gram