Jawabanmu

2014-06-13T10:17:22+07:00
PH=4-log5
[H+]=5x10^-4
[H+]=√Ka.M
5x10^-4=√2,5x10^-5xM
25x10^-8=2,5x10^-5xM
M=10^-2
=0,01M
Jadi, konsentrasi HA=0,01 M
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