Jawabanmu

2014-06-12T06:52:33+07:00
PH = -log [H⁺]
(p) pH=5
5= -log [H⁺]
jadi [H⁺] = 10⁻⁵
(q) pH =6
jadi dngan cara sama [H⁺] = 10⁻⁶
perbandingan p dan q = 10⁻⁵ : 10⁻⁶ coba di sederhanakan lagi

bisa diperjelas ga
ngitung [H+] pakek kalkulator di -anti log.
2014-06-12T07:59:09+07:00
P : pH = -log [H]
=5
[H]= 10^-5
q : pH= 6
[H]=10^-6
p:q=10 : 1