Jawabanmu

2014-06-11T21:40:06+07:00
[H⁺] = √Kh x M
= √10^-9 x 0,1
=√10^-10
= 10^-5

pH = -log [H]
= - log [10^-5]
= 5
2014-06-11T21:50:42+07:00