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2014-06-11T21:05:09+07:00
C6H5OONa ; Natrium benzoat
pH = 9
pOH = 6, OH- = 10^-6

OH- =  \sqrt{ \frac{Kw}{Ka} Ma }
10^-12=  \frac{10^{-14}}{6. 10^{-5} Mgaram}
6 x 10^-12 = 10^-9 x M
M = 6 x 10^-3

M =  \frac{gr}{Mr}  \frac{1000}{V}
6 x 10^-3 =  \frac{gr}{132}  \frac{1000}{100}
gram =  \frac{132 . 6. 10^{-3}}{10} = 0,0729 gram
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