Jawabanmu

2014-06-10T18:34:34+07:00
5. luas segitiga = alas.tinggi /2
alas = 3 cm
tinggi = CA^2=DC^2+AD^2
4^2=DC^2+1,5^2
16=DC^2+2,25
DC^2=16-2,25
DC^2=13,75
DC=√13,75
= 3,70 cm
luas segitiga = a.t/2
3.3,70/2 = 11,1cm^2
AB^2=AE^2+BE^2
3^2=AE^2+1^2
9=AE^2+1
AE^2=9-1
AE^2=8
AE=√8
AE=2,82cm