Jawabanmu

2014-06-10T14:08:07+07:00
M = 26,4gr
Mr=132
V = 2 liter
kb NH3=1,8x10^-5

M = (m/Mr) : V
= (26,4/132) : 2
= 0,2 : 2
= 0,1

[OH⁻] = √Kb x M
= √1,8x10^-5 x 0,1
= √1,8x10^-6
=1,3x10^-3

pOH = -log [OH]
= -log [1,3x10^-3]
= 3-log 1,3

pH = 14-pOH
= 14 - (3-log1,3)
= 11 + log 1,3