Jawabanmu

2014-06-10T08:34:46+07:00
P(1,2,3) , Q(3,1,5), dan R(4,5,6)
Panjang PQ = √{(3-1)²+(1-2)²+(5-3)²} = √(4 + 1 + 4) = √9 = 3 satuan
Panjang QR = √{(4-3)²+(5-1)²+(6-5)²} = √(1 + 16 + 1) = √18 = 3√2 satuan
Panjang PR = √{(4-1)²+(5-2)²+(6-3)²} = √√(9 + 9 + 9) = √27 = 3√3 satuan
Keliling Δ PQR = (3 + 3√2 + 3√3) satuan