Jawabanmu

Jawaban paling cerdas!
2014-06-09T18:50:28+07:00
1. y= sin³ (2x³-3x)
     = [sin (2x³-3x)]³
   y'= 3 sin (2x³-3x)² (6x²-3)
     = 18x²-9 sin² (2x³-3x)
2. f(x) = cos (2x-4 / 3x+5)
    f'(x) = -sin (2x-4 / 3x+5) (-5x-4 / 3x-2)
3. g(x) = x³ cos 2x
    g'(x)= 3x² -sin 2x (2)
          = 6x² -sin 2x
2 5 2