jumlah sepuluh suku pertama deret log 2 + log 6 + log 18 + log 54 + ... adalah...

1
sorry jangan berantem disini.
sorry ya tadi tu temen gue yangusil
woh syukur kalo gituu, maaf gan udah bikin kesel hehee
ya sama2
For Alfayet : Really put on new starters

Jawabanmu

2015-12-31T17:17:42+07:00
b = log 6 - log 2
   = log (6/2)
   = log 3

a = log 2

S₁₀ = n/2 ( 2a + 9b )
S₁₀ = 5(2 . log 2 + 9 . log 3)
S₁₀ = 10 log 2 + 45 log 3