Jawabanmu

Jawaban paling cerdas!
2014-06-08T22:30:36+07:00
Rumus laju radiasi
 \frac{Q}{t} = e.б.A.T⁴
e = emisivtas 
б = tetapan stefan boltzman
A = luas permukaan 
T = suhu mutlak (K)

laju kalor radiasi 1 :
diket : T = 27°C = 300 K
jawab :  \frac{Q}{t} = e.б.A.T⁴
           E = e.б.A.300⁴
           E = e.б.A.81 x 100⁴

laju kalor radiasi 2 :
diket : T = 327°C = 600 K
jawab :  \frac{Q}{t} = e.б.A.T⁴
            \frac{Q}{t} = e.б.A.600⁴
            \frac{Q}{t} = e.б.A.1296 x 100⁴

laju kalor radiasi 1 : laju kalor radiasi 2
e.б.A.81 x 100⁴ : e.б.A.1296 x 100⁴
e.б.A.81 x 100⁴ : e.б.A.1296 x 100⁴ (coret karna sama)
81 : 1296
1 : 16
E : 16E


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