Jawabanmu

2014-06-08T15:13:35+07:00
F(x) = (2x²+6)³ ⇒ f'(x) = 3(4x)(2x²+6)² = 12x(2x²+6)²

f(x) = 1/(3x-2) ⇒ f'(x) = (0 - 3)/(3x-2)²
                           f'(1) = -3/(3(1)-2) = -3/(3-2) = -3/1 = -3
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