Jawabanmu

2014-06-08T00:10:58+07:00
2.
Anggap:
u = x³ + 3x² + 1 maka du = 3x² + 6x dx
atau x² + 2x dx = du/3
(0,1) Int (x²+2x)/(x³ + 3x² + 1) dx
= (0,1) Int du/3 / u
= 1/3 (0,1) Int du/u
= 1/3 ln(x³ + 3x² + 1) batas (0,1)
= 1/3 [ln(5) - ln(1))
= 1/3 ln 5