Jawabanmu

2014-06-07T10:19:06+07:00
N NH4OH = M.V = 0,1.100 = 10 mmol
n NH4Cl = M.V = 0,1.100 = 10 mmol

[OH] = Kb.n NH4OH/n NH4Cl
[OH] = 10^-5.10/10
[OH] = 10^-5 M

pOH = -log[OH]
pOH = -log 10^-5
pOH = 5
pH = 14 - pOH
pH = 14 - 5
pH = 9

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