Jawabanmu

2014-06-06T22:54:50+07:00
Ph= 11 POH= 14 -11= 3 M= 10^-3 Mg(OH)2 -> Mg2+ + 2OH- S 2s 2s= 10^-3 s= 5.10^-6 ksp= [Mg2+ ]+[2OH-] S 2s^2 4s^3 4(5.10^-6)^3 4(125.10^-18) =5.10^-16
2014-06-07T03:15:19+07:00
PH=11 [H^+]= 10^-3
Mg(OH)2 --> Mg^+2  +   2OH^-
  5x 10^-4    5x10^-4      10^-3
[Mg(OH)2] = 5 x 10^-4

Ksp= 4s^3
      = 4x [5x10^-4]^3
      = 5 x10^-10
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