Jawabanmu

Jawaban paling cerdas!
2014-06-07T00:29:33+07:00
A) y = 2^x ⇔ log y = log 2^x ⇔ log y = xlog2 ⇔ x = logy/log2
   Jadi f^-1(x) = ²logx
b) y = 2^(x+5) ⇔ x+ 5 = ²logy ⇔ x = ²logy - 5
   Jadi f^-1(x) = ²logx - 5
c) y = ²log 3x
   ²log 2^y = ²log3 - ²log x
   ²logx = ²log3 - ²log2^y
           = ²Log 3/2^y
       x  = 3/2^y
   f^-1(x) = 3/2^y

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