Jawabanmu

2014-06-06T20:18:52+07:00
PH = 11
pH = pKw - pOH
11 = 14 - pOH
pOH = 3
[OH⁻] = 10⁻³

[OH⁻] =  \sqrt{Kb.Mb}
10⁻³ =  \sqrt{1x10-5 . Mb}
10⁻⁶ = 1x10⁻⁵ . Mb
Mb = 1x10⁻¹
Mb = 0,1
1 2 1