Jawabanmu

2014-06-05T18:41:33+07:00
f(x) = ax² + bx + c
f '(x) = 2ax + b

f '(0) = 0
2a(0) + b = 0
b = 0

f '(1)= 2
2a(1) + b = 2
2a = 2
a = 1


f(1) = x² + c = 2
          1 + c = 2
                 c = 1

f(x) = x² + 1
f(x+1) = (x+1)
² + 1
           = x
² + 2x + 1 + 1
           = x
² + 2x + 2