Jawabanmu

2014-06-04T00:37:02+07:00
F'(x)= 5.4 (3x²+2)⁴⁻¹ (3.2 x²⁻¹)
      = 20 (3x²+2)³ (6x)
      = 20 (6x) (3x²+2)³
      = (120x) (3x²+2)³
2014-06-04T00:45:02+07:00
f(x) = 5(3x^2 + 2)^4
f
'(x) = 4.5 .(3x^2 + 2)^3 . 6x
f'(x)=20(3x^2 + 2)^3 . 6x
f'(x)= 20 (9x^4+12x^2+4)
(3x^2 + 2).6x
f'(x)=20 (27x^6 + 18x^4 + 36x^4 + 24x^2 + 12x^2+8). 6x
f'(x)= 20 (27x^6 + 54x^4 + 36x^2 + 8) . 6x
f'(x)= 20 (162x^6 + 324x^4 + 216x^2 + 48x)
f'(x)= 3240x^6 + 6480x^4 + 4320x^2 + 960x