Jawabanmu

2014-06-03T13:49:09+07:00
Direaksikan dulu yaa.
NH₃ + HCl = NH₄CL
  6       4        -
  4       4        4
  2       -         4

[OH⁻] = Kb × mol sisa basa / mol garam
         = 10⁻⁵ × 2 / 4
         = 5 × 10⁻⁶
pOH = - log [OH⁻]
        = - log [5 × 10⁻⁶]
        = 6 - log 5
pH = 14 - pOH
     = 14 - (6 - log 5)
     = 8 + log 5 ≈ 8,699 (E)