Jawabanmu

2014-06-01T12:59:38+07:00
Pembahasan :
KOH → K+ + OH-
0,001//0,001//0,001

OH- = b. Mb
= 1∙ 0,001/10
= 0,0001 M
= 10-4 M
POH=- log⁡〖OH^- 〗
= - log 10-4
= 4
PH = 14 – 4
= 10
thank tanya lagi tentukan hidrolisis garam ba(oh)2