Jawabanmu

2014-05-31T18:57:07+07:00
A = 1, b= -1, c=1
x =  \frac{-b}{2a}
x =  \frac{-(-1)}{2(1)} =  \frac{1}{2}
D =  b^{2} - 4 a c
D =  (-1)^{2} - 4 (1)(1) = -3
y =  \frac{-D}{4a}
y =  \frac{-(-3)}{4(1)} =  \frac{3}{4}
jadi koordinat titik balik (x,y) = ( \frac{1}{2} ,  \frac{3}{4}