Jawabanmu

2014-05-30T17:03:15+07:00
 SO_{2} 1L = 8gr
 CH_{4} 5L = x gr

anggap  V_{1}  = volume  SO_{2} dan  V_{2}  = volume  CH_{4}

 \frac{ V_{1} }{V_{2} }  \frac{ m_{1} }{m_{2}}

 \frac{1}{5}  \frac{8}{x}

x =  \frac{8}{5} gr