Jawabanmu

2014-05-29T13:34:37+07:00
 f(2x-1) = 4x/2x+7
misal 2x-1 = A 
⇔ x =  \frac{A+1}{2}
f(A)=  \frac{ \frac{4(A+1)}{2} }{2( \frac{A+1}{2}) + 7 } =  \frac{4A+1}{2A+16}
f(x) =  \frac{4x+1}{2x+16}

y =   \frac{4x+1}{2x+16}
2xy + 16y = 4x + 1
2xy - 4x = 1-16y
x(2y - 4) = 1-16y
x =  \frac{1-16y}{2y-4}
f^{-1}(x)=  \frac{1-16x}{2x-4}