Jawabanmu

2014-05-29T13:26:34+07:00
* jumlah mol (n) O =  \frac{2}{22,4} = 0,089
* massa O = 0,089 x 16 = 1,424 g

semoga bs membantu

2014-05-29T13:46:25+07:00
 \frac{ v_{2} }{ n_{2} } =  \frac{v_{2} }{ n_{2} } 

 \frac{1 liter}{ \frac{1 gr}{16} } =  \frac{2 liter}{ \frac{x}{32} }
 \frac{16}{1} =  \frac{64}{x}
x =  \frac{64}{16}
x = 4 gram

makasih banyakya:)
tau cara nyelesain soal ini.. madu mempunyai massa jenis 9cm⁻³ mengandung glukosa C₆ H₁₂ O₆ 35% (Ar C=12 , H=1 , O=16) Konsentrasi glukosa dalam madu adalah? susah bgt:(
Mr C6H12O6 = 98. Jadi M = (10 x massa jenis x persen C6H12O6 ) / Mr = (10 x 9 x 96 ) / 98 = 3150/180 = 17, 5 M
ok..sama-sama
Mr C6H12O6 = 98. Jadi M = (10 x massa jenis x persen C6H12O6 ) / Mr = (10 x 9 x 96 ) / 98 = 3150/180 = 17, 5 M