Jawabanmu

2014-05-28T19:38:50+07:00
F(x) =  x^{2} (3-2x)^ \frac{1}{2}

U(x) =  x^{2}    ⇒  U'(x) = 2x
V(x) = (3-2x) ^\frac{1}{2}     ⇒   V'(x)= - \frac{2}{2 \sqrt{3-2x} }

f'(x) = U'(x) V(x) + V'(x) U(x) 
(2x) (  \sqrt{3-2x}) + ( x^{2} )(- \frac{2}{2 \sqrt{3-2x} } )
= 2x \frac{ \sqrt {3-2x} }{1}  \frac{2 x^{2} }{2 \sqrt{3-2x} }
= \frac{4x(3-2x)-2 x^{2} }{2 \sqrt{3-2x} }
 \frac{12x-10 x^{2} }{2 \sqrt{3-2x} }