Jawabanmu

2014-05-28T19:53:28+07:00
F(x) = 6x³+13x²+qx+12
f(1/3) = 0
6(1/3)³ + 13(1/3)² + (1/3)q + 12 = 0
2/9 + 13/9 + 3q/9 = -12
15 + 3q = -108
3q = -108-15
3q = -123
q = -41
f(x) = 6x³+13x²-41x+12
f(x)=(3x-1)(6x²+15x-36)
     =(3x-1)(2x-3)(3x+12)
    
2 4 2