Jawabanmu

2014-05-27T11:51:40+07:00
F' = 2x- 2 . √(x²-1) + (x²-2x) . 1/2 . (x²-1)^-1/2 . 2x
f'(2) = 4-2 . √4-1 + 4-4 ...
= 2√3
1 4 1
Jawaban paling cerdas!
2014-05-27T11:58:27+07:00
F(x) = (x²-2x)(x²-1)^1/2
f ' (x) = (2x-2)√(x²-1) + (x²-2x)(x)
                                    √(x² - 1)
f'(2) = (4-2)√(4-1) + ((4-4)4)/√(4-1)
       = 2√3 + 0
       = 2√3
dapat (x²-2x)(x) /√(x² - 1) dari mana ?