Jawabanmu

2014-05-27T11:02:23+07:00
Soal nmr 1
f (x) = x2 + 2x +1 absis 1
f (1) = 1+2+1 = 4
f aksen (x) = m = 2x + 2
m=2+2 =4

pers di (1,4) dn m =  4
y - b = m (x-a)
y -4 = 4 (x-1)
y = 4x - 4+4
y = 4x
 

soal nmr 2
f(x) = x3 - 6x2 + 9x -2 absis 1
f (1) = 1-6+9-2 = 2
f aksen (x) = m = 3x2 - 12x +9
m = 3-12+9 = 0

pers di (1,2) m = 0
y - b = m (x-a)
y-2 = 0 (x-1)
y = 2
caranya sama smua cm yg ini sy agak ragu soalnya m nya = 0