Jawabanmu

2013-12-13T13:34:19+07:00
y_1=y_2
x^2+mx+11=5x+7m
x^2+mx+11-5x-7m=0
x^2+(m-5)x+(11-7m)=0

berpotongan di dua titik, maka 
D>0
b^2-4ac>0
(m-5)^2-4(1)(11-7m)>0
m^2-10m+25-44+28m>0
m^2+18m-19>0
(m+19)(m-1)>0
m<-19  atau m>1