Jawabanmu

2014-05-25T12:55:55+07:00
[H+]=a.Ma
=2×0,02=0,04
pH=-log [H+]
=-log0,04
=2log4
H2SO4 → 2H+ + SO42-
[H+] = a.Ma
= 2.0,02
= 0.04
[H+] = 4.10-2
pH = - log [H+]
= - log 4.10-2
= 2 – log 4
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