Jawabanmu

2013-12-08T23:48:33+07:00
Misal U = x^3+1
du= 3x^2 dx
1/3 du = x^2 dx
 \int\limits^2_0 { \frac{1}{3}  x^{1/2} } \, dx =   \frac{1}{3} \frac{2}{3}  x^{3/2} =   \frac{2}{9}   \sqrt{x^{3} +1)^{3} }
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