Jawabanmu

2014-05-23T19:51:35+07:00
Misal u = 2x dan v = sin u
y = sin³ 2x
 \frac{dy}{dv} . \frac{dv}{du} . \frac{du}{dx} = (3)(v)²(cos u)(2)
 \frac{dy}{dv} . \frac{dv}{du} . \frac{du}{dx} = (3)(sin² 2x)(cos 2x)(2) = 6 sin²2x cos2x

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