Jawabanmu

Jawaban paling cerdas!
2014-01-27T21:15:24+07:00
A.)
a = 0,8
a= √ Ka/[HF]
Ka= 64 x 10^-3
[H+] = √  [HF] . Ka
[H+] =√ 0,1 x 64x10^-3
[H+]=√ 10^-1x64x10^-3
[H+]= 8 x 10^-2
Ph= - log [H+]
Ph=2-log8

b.)
Mol = M x V
m/Mr = M x V
3,7/ 40+(16x2)+(2x1) = M x 5
3,7/32 = 5M
0,05 = 5M
M= 0,01
Valensi  Ca(OH)2= 2
[H+]= M x val
[H+]= 0,01 x 2
[H+]= 0,02=2 x 10^-2
Ph= -log [H+]
Ph= 2-log2

maaf kalau salah ngitungnya :)
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